Or is it about the same, as the distance I’m traveling vertically remains unchanged?

  • finalarbiter@lemmy.dbzer0.com
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    1 day ago

    Also been a minute since I took physics 1, but IIRC, Work w = Force f × Displacement s in its simplest form.

    We can plug in Force f = Mass m × Acceleration a such that w=(ma)s to see that the primary components of work in this scenario are mass, acceleration, and displacement, so velocity doesn’t directly affect work.

    I guess you could do some further derivation to get it in as a term via a=d/dtv(t), but you still end up having to calculate acceleration anyways.