If humans can hang glide I don’t see why we couldn’t use those aerodynamic principles to try to glide a car hooked up to glider wings. It’s a real engineering challenge, but I feel like it would be possible to get some distance in a scenario where a car uses its wheels to go fast, drives off a cliff, deploys some kind of glider wings (or drive with the glider wings timed out to where the car gets to the cliff edge right at the point where the wings plus updraft provide enough lift) to get the vehicle to glide a substantial distance.
The terminal velocity of a penny is at least 40 km/h. A Porsche would be much higher. Assuming the Porsche fell that slowly and reached terminal velocity instantly, the cliff would have to be 20 km high for the Porsche to fall for 30 minutes. Given Mt. Everest is just under 9 km high, you would need more than 2 Mt. Everests of height for your cliff to make this happen.
Based on all that, the terminal velocity of a Porsche is irrelevant.
My 1975 was tuned for distance. When I drove it from Key Largo to Seattle, it did 35mpg average over the 3500 miles I drove. That car was lost in an accident, sadly.
25 miles per gallon. 30 minutes would be 12.5 miles on half a gallon.
My current one does about 25-30 mpg. It weighs 1950 pounds. So, yes. It can comfortably do half an hour on one gallon or so and have fuel left to get me to a refill.
They have flat 4 two liter VW engines. Extremely efficient if tuned correctly. One top of that, there is a direct 1 to 1 drop-in electric kit for these. When my current engine dies, I have an electric kit I’ll put into it to make it an 914E.
Literally the first sentence:
Can your Porsche 914 fly for half an hour on $5 of fuel ?
Off a cliff yeah
It would have to be a very high cliff.
If humans can hang glide I don’t see why we couldn’t use those aerodynamic principles to try to glide a car hooked up to glider wings. It’s a real engineering challenge, but I feel like it would be possible to get some distance in a scenario where a car uses its wheels to go fast, drives off a cliff, deploys some kind of glider wings (or drive with the glider wings timed out to where the car gets to the cliff edge right at the point where the wings plus updraft provide enough lift) to get the vehicle to glide a substantial distance.
Seems horribly dangerous but not impossible.
Anyone know the terminal velocity of a falling Porsche 914? lol
The terminal velocity of a penny is at least 40 km/h. A Porsche would be much higher. Assuming the Porsche fell that slowly and reached terminal velocity instantly, the cliff would have to be 20 km high for the Porsche to fall for 30 minutes. Given Mt. Everest is just under 9 km high, you would need more than 2 Mt. Everests of height for your cliff to make this happen.
Based on all that, the terminal velocity of a Porsche is irrelevant.
My 1975 was tuned for distance. When I drove it from Key Largo to Seattle, it did 35mpg average over the 3500 miles I drove. That car was lost in an accident, sadly.
25 miles per gallon. 30 minutes would be 12.5 miles on half a gallon.
My current one does about 25-30 mpg. It weighs 1950 pounds. So, yes. It can comfortably do half an hour on one gallon or so and have fuel left to get me to a refill.
They have flat 4 two liter VW engines. Extremely efficient if tuned correctly. One top of that, there is a direct 1 to 1 drop-in electric kit for these. When my current engine dies, I have an electric kit I’ll put into it to make it an 914E.
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Point to me in your quote where it talks about distance.